2024 WAEC CHEMISTRY: 2024 WAEC MAY/JUNE Chemistry Practical Answers (9305)

Tuesday 18th August 2020
Chemistry 3(Practical) (Alternative A)(1st set) – 9:30am – 11:30pm (2hrs)
Chemistry 3 (practical)(Alternative A) (2nd set) – 12:00pm – 2:00pm

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For No. 1... PLEASE REMEMBER TO USE YOUR'S SCHOOL'S AVERAGE TITRE VALUE(AVERAGE VOLUME OF ACID). WE USED 15.26cm3, TRY TO KNOW YOUR SCHOOL'S AVERAGE TITRE VALUE. ASK YOUR CHEMISTRY TEACHER. THEN, ANYWHERE YOU SEE 15.26cm3 IN MY CALCULATION, PUT YOUR SCHOOL'S OWN AND RE-CALCULATE. THIS IS VERY IMPORTANT!!!

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Pls, use your school endpoints.
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(1a) 
In a tabular form

Burette Reading|1st reading|2nd reading|3rd reading
Final |15.25|0.00|45.79|
Initial|0.00||15.25|30.53|
Volume of acid used |15.25|15.28|15.26

Average volume of acid used = 15.25 + 15.26/2
= 15.255cm³
=15.26cm³

(1bi) 
Given: Mass of conc of A = 5g/500cm³ = 5g/0.5dm³
Ca = 10g/dm³

A is HNO3
Therefore; Molar mass = 1+14+(16×3)
= 15+48
=63g/mol

Molarity of A = gram conc/molar mass
Ca = 10/63 = 0.1587mol/dm³

(1bii) 
Using CaVa/CbVb = nA/nB
With reacting equation:  
HNO3 +NaOH-->NaNO3 + H2O
nA = 1, nB = 1
0.1587×15.26/Cb×25.00 = 1/1
25Cb = 0.1587×15.26
CB = 0.1587×15.26/25
CB = 0.09687mol/dm³

(1biii)
B is NaOH
Molar mass = 23+16+1
=40g/mol
Conc of B in g/dm³ = molarity×molar mass
=0.09687×40
=3.8748g/dm³

(1biv) 
No of moles present in 250cm³ of NaOH is 
= molar conc. × volume 
= 0.09687 × 250/1000
= 0.0242 moles 

Mole ratio of NaOH and NaNO3 is 1:1
No of moles of NaNO3 which reacted is 0.0242
Mass of NaNO3 formed = molar mass × no of moles 
= 85 × 0.0242
=2.057grams

(2a)
TEST: C+burning splint

OBSERVATION: Sample C burst into flame. It burns with non-smoky blue flame without soot. Colourless gas that turns wet blue litmus paper faint red and turns like water milky is present.

INFERENCE: C is volatile and flammable. The gas is CO2 from combustion of a saturated organic compound.

(2bi)
TEST: C + distilled water + shake

OBSERVATION: Clear or colourless solution is observed

INFERENCE: C is miscible with water

(2bii)
TEST: C + Acidified K2Cr207

OBSERVATION: Orange colour of K2Cr207 solution turns pale green and eventually pale blue on cooling

INFERENCE: C is a reducing agent

(2C)
TEST: D + C + 10% NaOH + Shake

OBSERVATION: D dissolves slowly in C and produces a reddish-brown solution. The reddish-brown solution turns yellow precipitate. The precipitate has an antiseptic odour
INFERENCE: D is soluble in organic solvents

(2d)
The compound belongs to the class of secondary alkanol

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(3ai)
Zinc nitrate

(3aii)
2 Zn(NO 3 )2 ----->2 ZnO + 4 NO 2 + O 2

(3aiii)
It turns white when cold from its yellow colour when it was hot.

(3b)
Pipette/measure 50.0cm3 of the stock solution into a 250
cm3 volumetric flask (containing some distilled water). Shake/swirl and add more distilled water until the mark is reached.

(3c)
Al2(SO4)3 - turns blue litmus red
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